编写一个程序，只要输入年月日，就能回答那天是星期几。

输入一个日期，包括年、月、日。(一组测试数据)

输出这个日期是星期几。

输入：

1 1 1

2 1 1

2006 7 10

输出：

Monday

Tuesday

Monday

代码：

//====================================================//名称：计算生日是星期几(0078)//作者：郭成涛//时间：2015-11-22//简介：编写一个程序，只要输入年月日，就能回答那天是星期几。//====================================================#include
        
         int main(){    int mon[12]={
      31,28,31,30,31,30,31,31,30,31,30,31};    int y,m,d,i,sum=0,j=0;    scanf("%d%d%d",&y,&m,&d);    for(i=1;i
         
          1&&(y%4==0&&y%100!=0)||y%400==0)            sum++;    }    sum=sum+d;           //计算天    j=sum%7;    switch(j)    {    case 0:printf("Sunday\n");break;    case 1:printf("Monday\n");break;    case 2:printf("Tuesday\n");break;    case 3:printf("Wednesday\n");break;    case 4:printf("Thursday\n");break;    case 5: printf("Friday\n");break;    case 6: printf("Saturday\n");break;    }    return 0;}
         
        

 换一种方式：

#include 
        
         int main(){int y, m, d, i;int year, day;int month[] = {
      0, 31, 0, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};char week[][10] = {
      "Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"};while (scanf("%d %d %d", &y, &m, &d) == 3){year = 1;day = d;while (year < y){day += year%400==0||(year%4==0&&year%100!=0) ? 366 : 365;year++;}if (y%400==0||(y%4==0&&y%100!=0)) month[2] = 29;else month[2] = 28;for (i=1; i